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By Eugene P Wigner, J J Griffin

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2. We are therefore looking for a wavefunction that represents a particle which is equally likely to be moving in either direction. 2) The sine function satisfies the boundary conditions when k = nn/L,where . When x = 0, w = n is a positive integer, known as a 0 and when x = L, t,u = 2iAsin(nz) = 0. (7) with N = 2iA and n = 1, 2, 3, etc. 4) The potential energy, V, is zero and therefore the total energy, E, equals T. Thus: E = - n2h2 with n = 1, 2, 3, etc. 8mL2 It should be noted that n = 0 is not allowed because this would correspond to the wavefunction being zero everywhere, and we would have lost our particle.

Here the point of impact is localized and the momentum after impact can be determined from the surface corrugation. Although heavy atoms have wave-like properties, the wavelength is very much shorter than the interatomic distances found in solids, and diffraction is not observed. When electrons or much lighter atoms are used, however, it becomes impossible to give precise trajectories because the wave-like properties of these particles control the scattering. Take electron diffraction, for example.

Or does this seem too absurd to be taken seriously? 3 Uncertainty with Particle-in-a-box A similar uncertainty arises with the particle in a box. Although the energy of the particle is known, there is an uncertainty in the momentum because it is not possible to know at any given instant whether the particle is moving from left to right or right to left. Combining the equations for energy and momentum, E = n2h2/8mL2and p2 = 2mE, it can be seen that p = k nh/2L. There is, therefore, an uncertainty in the momentum, Ap,, equal to nh/2L.

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