By Grosche C.
During this lecture a brief advent is given into the idea of the Feynman direction critical in quantum mechanics. the final formula in Riemann areas might be given in response to the Weyl- ordering prescription, respectively product ordering prescription, within the quantum Hamiltonian. additionally, the idea of space-time alterations and separation of variables can be defined. As basic examples I speak about the standard harmonic oscillator, the radial harmonic oscillator, and the Coulomb strength.
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Additional info for An introduction into the Feynman path integral
Example text
Similarly we can state a path integral identity for the modified P¨osch-Teller potential which is defined as V (η,ν) ν 2 − 41 ¯ 2 η 2 − 41 h . 3) This can be achieved by means of the path integration of the SU(1, 1) group manifold. One gets NM K (M P T ) ′′ ′ (r ′′ ) exp Φn(η,ν) ∗ (r ′ )Φ(η,ν) n (r , r ; T ) = − n=0 ∞ + 0 dp Φp(η,ν) ∗ (r ′ )Φ(η,ν) (r ′′ ) exp p ih ¯T 2(k1 − k2 − n) − 1 2m − ih ¯T 2 p . 4) Introduce the numbers k1 , k2 defined by: k1 = 21 (1 ± ν), k2 = 21 (1 ± η), where the correct sign depends on the boundary conditions for r → 0 and r → ∞, respectively.
Thus we try to replace LCl by a simpler expression and hope that Vc + ∆VW eyl is simple enough. 3). 52) and thereby derive an expression for Vc . 2), R = r (not fixed), and expand it in terms of ∆r and ∆θν . 54) with Vc (r (j) , {θ (j) }) = 1 ¯2 h 1 1 + + · · · + (j) (j) (j) 8mr (j) 2 sin2 θ1 sin2 θ1 . . 55) (Vc is the same whether or not ∆r (j) = 0). The result is that the potential Vc generated by these steps cancels exactly ∆VW eyl (r, {θ})! 56) where x˙ 2 has to be expressed in polar coordinates.
Let x ∈ Rn and define µ = x′ + x′′ , ν = x′ · x′′ , then 1 ∂ (D−2) ′′ ′ K (x , x ; T ) 2π ∂ν 1 − i ωT mω ∂ = K (D−2) (x′′ , x′ ; T ). 27) Introducing furthermore ξ = 21 (|x′ + x′′ | + |x′′ − x′ |), η = 21 (|x′ + x′′ | − |x′′ − x′ |) we obtain for D = 1, 3, 5 . . 28) respectively, 1 G(D) (x′′ , x′ ; E) = − 2 ∂ ∂ 1 ξ − η × 2 η − ξ2 ∂ξ ∂η m D E Γ − π¯hω 2 ¯ω h mω + ¯h 1 2π D−1 2 D− D + E 2 h ¯ω D−1 2 2mω ξ ¯h D− D + E 2 h ¯ω − 2mω η . 29) Let us note that the most general solution for the general quadratic Lagrangian is due to Grosjean and Goovaerts [52, 53].